3x^2-245x-1500=0

Solution for 3x^2-245x-1500=0 equation:

3x^2-245x-1500=0

a = 3; b = -245; c = -1500;
Δ = b2-4ac
Δ = -2452-4·3·(-1500)
Δ = 78025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{78025}=\sqrt{25*3121}=\sqrt{25}*\sqrt{3121}=5\sqrt{3121}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-245)-5\sqrt{3121}}{2*3}=\frac{245-5\sqrt{3121}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-245)+5\sqrt{3121}}{2*3}=\frac{245+5\sqrt{3121}}{6}
$